# how to solve this problem??

ive written a code for the following problem but it doesnt work properly according to the question. can anyone help??
PROBLEM:://WCP to enter to enter 5 integers in a single array.
If the number is greater than 11
it doesnt store it and prints "Please reenter the number"
it displays the same message
EVERY TIME a number>11 is entered//
[code]
#include

void main()
{
int num[5],i;

printf("
pls enter 5 numbers::");

for(i=0; i<5; i++)

{ scanf("%d", &num[i]);

if(num[i]>11)
{
printf("
Pls reenter the number");
}
scanf("%d", &num[i-1]);

}

for(i=0; i<5; i++)
printf("
The numbers are::
%d", num[i]);

}
[/code]

• The main trouble with your code is that the second scanf should be within the test function and the index should be i:

[code]
if(num[i]>11)
{
printf("
Pls reenter the number");
scanf("%d", &num[i]);
}

}

[/code]

You can find other suggestions in a separate post I made asking for information on the scanf() function:

http://www.programmersheaven.com/mb/beginnercpp/402619/402619/a-scanf-question-for-the-gurus/?S=B20000#402619

Take Care,
Ed
• #include
#include

int main()
{
int num[5],i;
printf("
Pls enter 5 numbers : ");
for(i=0; i<5; i++){
scanf("%d", &num[i]);
if (num[i]>11) {
printf("
Pls reenter number %d: ", i+1);
i--;
continue;
}
}
printf("
The numbers are:");
for(i=0; i<5; i++)
printf("
%d %d", i+1, num[i]);
printf("

");
system("PAUSE");
return 0;
}

• Just for grins, how about something like

[code]
#include
#include
#include

int main(void) {

int num[5] = { 0 }, i = 0;
char nbuf[32] = { 0 };

while(i < 5) {

do {

printf("%s number %d
", num[i] > 11 ? "please reenter" : "enter", i + 1);
fgets(nbuf, sizeof nbuf, stdin);

} while((sscanf(nbuf, "%d", &num[i]) != 1) || num[i] > 11);

i++;
}

printf("

The numbers are: ");

for(i=0; i<5; i++)
printf("%d ", num[i]);

return (0);
}[/code]

HTH

• Thanks a lot!!!
I got three replies, but yours was the only one understood clearly and it is working perfectly.
Thanks again.
• Thanks a lot!!!
I got three replies, but yours was the only one understood clearly and it is working perfectly.
Thanks again.
• If you want you can leave out the line

[code]continue;[/code]

since there is no code between the end of the if block and the closing of the for block.

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