File size

Unknown

How would I go about to determine the size of a file?

Unknown

: How would I go about to determine the size of a file?

At his moment I have 2 methods in my mind.

method 1) Open the file, move to the end of it by using AX=4202h INT 21h and the file size will be at DX:AX if no error occured.

INT 21h, function 42 (move file pointer of an open file)

AH = 42h

AL = 0 (move from beggining of file) or 1 (move from currect possition of file) or 2 (move from the end of file)

BX = File handle

CX:DX = number of bytes to move.

example:

; open the file

MOV AX,3D02h

MOV DX,OFFSET FileName

INT 21h

; Save handle in BX

MOV BX,AX

;Move at the end of the file

MOV AX,4202h

XOR CX,CX ;

XOR DX,DX ;Zero bytes from the end of file

INT 21h

; now CX:DX contanis file length.

; close file

MOV AH,3Eh

INT 21h

FileName: db 'file1.tmp',0

Method 2) By using find first function and then getting the filesize from the DTA.

the DTA is located at CS:0080h, but if we want to change it's location ,we can do it by using function 1Ah of INT 21h.

FUNCTION 1Ah (Set DTA) of INT 21h

AH = 1Ah

DS:DX = New location of DTA (Disk Transfer Area)

FUNCTION 4Eh (Find first matching file) of INT 21h

AH = 4Eh

CX = Attributes OF file to search (I thing this matters only if you are searching for volume label, so in any other situatoin use 3Fh for CX)

DS:DX = pointer to the filename or file mask.

and now the DTA format

offset 15h attrubute of file (byte)

16h File time (word)

18h file date (word)

1Ah file size (dword)

1Eh name of file found

Example:

; in this example we will take the default DTA adress, although it's a good idea to change the DTA adress in general

MOV AH,4Eh

MOV CX,03Fh

MOV DX,OFFSET FileMask

INT 21h

MOV DX,WORD PTR [80h + 1Ah] ; Remember 80h is the default DTA adress

MOV CX,WORD PTR [80h + 1Ah + 2]

;now CX:DX contains the file size

Hope I helped

/Andreas




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