passing text to a function

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How do you pass text to a function as it is done in printf? In the prototyping of printf it mentions taking ... as an argument, but how is printf("hello world") handeled? Is hello world read into a temporary array? Thanks in advance.

Unknown

: How do you pass text to a function as it is done in printf? In the prototyping of printf it mentions taking ... as an argument, but how is printf("hello world") handeled? Is hello world read into a temporary array? Thanks in advance.

Generally you pass a pointer to the string on the stack.

Matthew Gross


URL:http://acheronx.resnet.tamu.edu

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: How do you pass text to a function as it is done in printf? In the prototyping of printf it mentions taking ... as an argument, but how is printf("hello world") handeled? Is hello world read into a temporary array? Thanks in advance.

This is copied directly from Turbo C++'s Help:

#include

#include

/* calculate sum of a 0 terminated list */

void sum(char *msg, ...)

{

int total = 0;

va_list ap;

int arg;

va_start(ap, msg);

while ((arg = va_arg(ap,int)) != 0) {

total += arg;

}

printf(msg, total);

va_end(ap);

}

int main(void) {

sum("The total of 1+2+3+4 is %d
", 1,2,3,4,0);

return 0;

}

I hope that helps. I've never actually made one but this is how it's done.

-Xotor-

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