How do you read a text file into an array?

Unknown

I am trying to read a text file into an array. The text file consists of 50 codes that are 6 characters long. The file looks like this:

AD4513 DS4552 FD3333 FG5564 ect...,

all fifty codes are in one line seperated by one space. I wrote this short program to check if I was correctly reading the file into the array so I had the program output to what was in element 0 of the array. Instead of having just one 6 character code in it, it seems to read the entire line of 50 codes into one element. Can anyone tell me what I am doing wrong? I can't figure out how to read one code at a time into the array. How do I get the program to stop when it gets to a space and then read the next code it reads into a new element of the array? From what I can see, I my code reads the entire file as one continous code. Thanks for any suggestions.

#include

FILE *fptr;

void main()

{

char pcodes[50][6];

int i;

if((fptr=fopen("parts6.txt", "r"))==NULL)

printf("The file could not be opened.
");

else{

i=0;

while(!feof(fptr)){

fscanf(fptr, "%s", &pcodes[i]); /* reads file into string array */

i++;

}/* end while */

fclose(fptr);}

printf("This is pcode0 %s
", &pcodes[0]);

}

Unknown

: I am trying to read a text file into an array. The text file consists of 50 codes that are 6 characters long. The file looks like this:

: AD4513 DS4552 FD3333 FG5564 ect...,

: all fifty codes are in one line seperated by one space. I wrote this short program to check if I was correctly reading the file into the array so I had the program output to what was in element 0 of the array. Instead of having just one 6 character code in it, it seems to read the entire line of 50 codes into one element. Can anyone tell me what I am doing wrong? I can't figure out how to read one code at a time into the array. How do I get the program to stop when it gets to a space and then read the next code it reads into a new element of the array? From what I can see, I my code reads the entire file as one continous code. Thanks for any suggestions.

: #include

: FILE *fptr;

:

: void main()

: {

: char pcodes[50][6];

: int i;

: if((fptr=fopen("parts6.txt", "r"))==NULL)

: printf("The file could not be opened.
");

: else{

: i=0;

: while(!feof(fptr)){

: fscanf(fptr, "%s", &pcodes[i]); /* reads file into string array */

: i++;

: }/* end while */

: fclose(fptr);}

: printf("This is pcode0 %s
", &pcodes[0]);

: }

/*-----------------------------------------------------*/

//You might want to read in the file one //character at a time

//Hard coded it looks like this

char ch;

int x,y;

...

for(x = 0;x<50;x++)<br>
{

for(y = 0;y<6;y++)<br>
{

pcodes[x][y]= ( fgetc(fptr));

}

}

//END OF PROGRAM

...

//soft- coded looks like this

//see if you can find the logic error

x = y = 0;

while ((ch=fgetc(fptr)) != EOF)

if (ch == 32)

{

x++;

y = 0;

}

pcodes[x][y] = ch;

}//end of while

Unknown

>>I am trying to read a text file into an array. >>The text file consists of 50 codes that are 6 >>characters long. The file looks like this:

>>AD4513 DS4552 FD3333 FG5564 ect...,

#include

#include

void main(void)

{

FILE *fptr;

char pcodes[50][7]; //pay close attention! I've changed the [50][6] to [50][7]

//'coz you need a null terminated string!

int i = 0;

if((fptr=fopen("parts6.txt", "rb"))==NULL)

printf("The file could not be opened.
");

else

{

memset(pcodes, 0, sizeof(pcodes)); //reset the entire array to NULL

for(;;)

{

fread(pcodes[i++], 6, sizeof(char), fptr); //read 6 chars from input

if(feof(fptr))//check if it's the end of file

break;

fseek(fptr, 1L, SEEK_CUR);

}

fclose(fptr);

printf("This is pcode0 %s
", pcodes[0]);

}

}


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