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# Testing coming up this thursday. need help!

Posts: 2Member
Implement the function manipulateVector to generate the output shown below by using ONLY the functions listed in your reference list. This means that you cannot use any literals [color=Red](NO numbers)[/color] and [color=Red]you cannot use iterators.[/color]

For example, in the output below, the first line prints out the vector and the second line prints out a new vector from which the element at position 2 has been removed. You cannot use v.erase(2) ? you must use only the functions in the reference list and NO numbers.

Therefore, the correct implementation is:
v.erase(v.begin() + v.back());
where v.begin() will point to element 1 at index 0 and v.back()returns the last element, which is 2, making the iterator point to index 2.

1 4 9 8 6 5 7 3 2
1 4 8 6 5 7 3 2
1 8 6 5 7 3 2
1 8 1 6 5 7 3 2
1 8 1 1 6 5 7 3 2
1 2 8 1 1 6 5 7 3 2
2 3 7 5 6 1 1 8 2 1

By the way this exercise uses the stl.
i started by hardcoding the numbers into a vector.
So made a vector v. Then i inserted "1 4 9 8 6 5 7 3 2" by using the function v.push_back() for each number.
Now that i have a vector filled with the numbers above, I can't figure out how I'm supposed to print the items in the vector
without using an iterator! seems almost impossible