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helen1974helen1974 Member Posts: 4
Hi all,

I am new to java and really need some advice, my lecturer wants me to write the following code (which works), but is there a shorter way to write this, i believe so but will stand corrected.

The idea here is that there are 3 rows and 4 columns of numbers, which we want to multiply by 3, then identify the position by row and column of the largest number, can you help ?


import java.util.Scanner;
public class page63
{
public static void main(String []args)
{
Scanner myinput = new Scanner(System.in);
int [][] table = {{0,1,11,3},{8,9,10,11},{4,5,6,1}};
int i,j;
int NO_OF_ROWS = 3;
int NO_OF_COLS = 4;
int max_val = table[0][0];
int max_row_pos = 0;
int max_col_pos = 0;

for(i=0; i < NO_OF_ROWS; i++)
{
for(j=0; j < NO_OF_COLS; j++)
{
table[i][j] = table[i][j]*3;
}
}
for(i=0; i < NO_OF_ROWS; i++)
{
for(j=0; j < NO_OF_COLS; j++)
{
System.out.print(table[i][j] + " " );
}
System.out.println();
}
for(i=0; i < NO_OF_ROWS; i++)
{
for(j=0; j < NO_OF_COLS; j++)
{
if(table[i][j]>max_val)
{
max_val=table[i][j];
max_row_pos=i+1;
max_col_pos=j+1;
}
}
}
System.out.println(" ");
System.out.println("Max value = "+max_val);
System.out.println(" ");
System.out.println("it's co-ordinates are row "+max_row_pos+" column "+max_col_pos);
}
}
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