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circuz_phreak
Posts: **49**Member

in Java

I have a static method created called:

public static long factorial(int n){ //open factorial

int i;

long result=1;

for (i=1; i <= n; i++) {

result *= i;

}

return result;

}

I have no idea how to call it in the main. I leave public class open and close it after factorial and close main before factorial. But i really have no idea how to call it or use the return value. I need to compute factorials (0 to 11) and use them as part of an equation. (the taylor cosine approximation and have them print to screen. Kind of stuck....thanks

public static long factorial(int n){ //open factorial

int i;

long result=1;

for (i=1; i <= n; i++) {

result *= i;

}

return result;

}

I have no idea how to call it in the main. I leave public class open and close it after factorial and close main before factorial. But i really have no idea how to call it or use the return value. I need to compute factorials (0 to 11) and use them as part of an equation. (the taylor cosine approximation and have them print to screen. Kind of stuck....thanks

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## Comments

6,349Member:

: public static long factorial(int n){ //open factorial

: int i;

: long result=1;

: for (i=1; i <= n; i++) {

: result *= i;

: }

: return result;

: }

:

: I have no idea how to call it in the main. I leave public class open and close it after factorial and close main before factorial. But i really have no idea how to call it or use the return value. I need to compute factorials (0 to 11) and use them as part of an equation. (the taylor cosine approximation and have them print to screen. Kind of stuck....thanks

:

You can use the class name as object in this case. For example:

[code]

sinPhi = Math.sin(phi); // takes the sinus of variable phi

System.out.println(Math.sqrt(4)); // Prints 2

[/code]

where Math is a class full of static mathematics routines. See javaDoc: http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Math.html

- Spam

0 · Vote Down Vote Up · Share on Facebook49Member- Spam

0 · Vote Down Vote Up · Share on Facebook6,349Member:

I would start by looking up the taylor series. Then write it down in english or pseudocode, which steps need to be calculated and in which order. Be mindful of loops and if-statements along the way. Finally you can translate what you have written down into Java.

If you write it down correctly and precisely, then the last step is very easy. In a lot of cases writing such things down will teach you to recognize loops and other statements more clearly. In some cases you might want to try various approaches. It is often helpful to break the complete calculation down in smaller parts and focus on each of those individual parts. Once the individual parts work correctly, then link them together to form the whole.

- Spam

0 · Vote Down Vote Up · Share on Facebook49Membervalue = (Math.pow(-1, terms) * Math.pow(radAngle, (2*terms))) / factorial((2 * terms))); // inside a for loop in the main {}

terms changes because its inside a for loop, 1 - 11 terms, rad angle is the input by the user, and factorial calls the method.

The last part enters (2 * terms) into the factorial method to gimme a number. However the way this works out is Double * double / long. I get precision errors. Now if my answer is a long how can it be in decimal form? it recommends i cast it and write (long) infront of both doubles. The numbers i'm computing are going to have ALOT of decimal places. What do i do?

Thanks for all your help!!!

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0 · Vote Down Vote Up · Share on Facebook6,349Member:

: value = (Math.pow(-1, terms) * Math.pow(radAngle, (2*terms))) / factorial((2 * terms))); // inside a for loop in the main {}

:

: terms changes because its inside a for loop, 1 - 11 terms, rad angle is the input by the user, and factorial calls the method.

:

: The last part enters (2 * terms) into the factorial method to gimme a number. However the way this works out is Double * double / long. I get precision errors. Now if my answer is a long how can it be in decimal form? it recommends i cast it and write (long) infront of both doubles. The numbers i'm computing are going to have ALOT of decimal places. What do i do?

:

: Thanks for all your help!!!

:

:

I would cast the long into a double, because a long is an integer type, and you want to have the decimal places.

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0 · Vote Down Vote Up · Share on Facebook49Member- Spam

0 · Vote Down Vote Up · Share on Facebook49MemberI'm just confused now how I get all of the numbers to add up. Value = 1, then -0.5, then 0.04661. (theres alot more). But if its inside a for loop I'm not sure how to add them up, Term 1 = 1, term 2 = 1 + (-0.5), Term 3 (Term 2 + 0.04661); But i'm somewhat lost. I thought it was simple but everything i've tried fails.

- Spam

0 · Vote Down Vote Up · Share on Facebook6,349Member:

: I'm just confused now how I get all of the numbers to add up. Value = 1, then -0.5, then 0.04661. (theres alot more). But if its inside a for loop I'm not sure how to add them up, Term 1 = 1, term 2 = 1 + (-0.5), Term 3 (Term 2 + 0.04661); But i'm somewhat lost. I thought it was simple but everything i've tried fails.

:

I would use a function to calculate the terms based on some counter:

[code]

double taylor = 0;

for (int i = 0; i < Max; i++) {

taylor = taylor + term(i);

}

[/code]

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0 · Vote Down Vote Up · Share on Facebook49Member- Spam

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