It looks like you're new here. If you want to get involved, click one of these buttons!

- 140.9K All Categories
- 104.5K Programming Languages
- 6.4K Assembler Developer
- 1.8K Basic
- 39.7K C and C++
- 4.2K C#
- 7.9K Delphi and Kylix
- 4 Haskell
- 9.6K Java
- 4.1K Pascal
- 1.3K Perl
- 1.9K PHP
- 507 Python
- 48 Ruby
- 4.3K VB.NET
- 1.6K VBA
- 20.8K Visual Basic
- 2.6K Game programming
- 310 Console programming
- 88 DirectX Game dev
- 1 Minecraft
- 109 Newbie Game Programmers
- 2 Oculus Rift
- 8.9K Applications
- 1.8K Computer Graphics
- 726 Computer Hardware
- 3.4K Database & SQL
- 521 Electronics development
- 1.6K Matlab
- 627 Sound & Music
- 256 XML Development
- 3.3K Classifieds
- 191 Co-operative Projects
- 180 For sale
- 189 FreeLance Software City
- 1.9K Jobs Available
- 600 Jobs Wanted
- 201 Wanted
- 2.9K Microsoft .NET
- 1.7K ASP.NET
- 1.1K .NET General
- 3K Miscellaneous
- 3 Join the Team
- 2 User Profiles
- 353 Comments on this site
- 59 Computer Emulators
- 1.8K General programming
- 178 New programming languages
- 608 Off topic board
- 168 Mobile & Wireless
- 42 Android
- 124 Palm Pilot
- 335 Multimedia
- 151 Demo programming
- 184 MP3 programming
- 0 Bash scripts
- 18 Cloud Computing
- 52 FreeBSD
- 1.7K LINUX programming
- 367 MS-DOS
- 0 Shell scripting
- 320 Windows CE & Pocket PC
- 4.1K Windows programming
- 889 Software Development
- 405 Algorithms
- 68 Object Orientation
- 86 Project Management
- 88 Quality & Testing
- 234 Security
- 7.5K WEB-Development
- 1.8K Active Server Pages
- 61 AJAX
- 2 Bootstrap Themes
- 55 CGI Development
- 19 ColdFusion
- 222 Flash development
- 1.4K HTML & WEB-Design
- 1.4K Internet Development
- 2.2K JavaScript
- 33 JQuery
- 285 WEB Servers
- 119 WEB-Services / SOAP

Welcome to the new platform of Programmer's Heaven! We apologize for the inconvenience caused, if you visited us from a broken link of the previous version. The main reason to move to a new platform is to provide more effective and collaborative experience to you all. Please feel free to experience the new platform and use its exciting features. Contact us for any issue that you need to get clarified. We are more than happy to help you.

circuz_phreak
Posts: **49**Member

in Java

I have a static method created called:

public static long factorial(int n){ //open factorial

int i;

long result=1;

for (i=1; i <= n; i++) {

result *= i;

}

return result;

}

I have no idea how to call it in the main. I leave public class open and close it after factorial and close main before factorial. But i really have no idea how to call it or use the return value. I need to compute factorials (0 to 11) and use them as part of an equation. (the taylor cosine approximation and have them print to screen. Kind of stuck....thanks

public static long factorial(int n){ //open factorial

int i;

long result=1;

for (i=1; i <= n; i++) {

result *= i;

}

return result;

}

I have no idea how to call it in the main. I leave public class open and close it after factorial and close main before factorial. But i really have no idea how to call it or use the return value. I need to compute factorials (0 to 11) and use them as part of an equation. (the taylor cosine approximation and have them print to screen. Kind of stuck....thanks

About & Contact / Terms of use / Privacy statement / Publisher: Lars Hagelin

Programmers Heaven articles / Programmers Heaven files / Programmers Heaven uploaded content / Programmers Heaven C Sharp ebook / Operated by CommunityHeaven LLC

© 1997-2013 Programmersheaven.com - All rights reserved.

## Comments

6,349Member:

: public static long factorial(int n){ //open factorial

: int i;

: long result=1;

: for (i=1; i <= n; i++) {

: result *= i;

: }

: return result;

: }

:

: I have no idea how to call it in the main. I leave public class open and close it after factorial and close main before factorial. But i really have no idea how to call it or use the return value. I need to compute factorials (0 to 11) and use them as part of an equation. (the taylor cosine approximation and have them print to screen. Kind of stuck....thanks

:

You can use the class name as object in this case. For example:

[code]

sinPhi = Math.sin(phi); // takes the sinus of variable phi

System.out.println(Math.sqrt(4)); // Prints 2

[/code]

where Math is a class full of static mathematics routines. See javaDoc: http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Math.html

49Member6,349Member:

I would start by looking up the taylor series. Then write it down in english or pseudocode, which steps need to be calculated and in which order. Be mindful of loops and if-statements along the way. Finally you can translate what you have written down into Java.

If you write it down correctly and precisely, then the last step is very easy. In a lot of cases writing such things down will teach you to recognize loops and other statements more clearly. In some cases you might want to try various approaches. It is often helpful to break the complete calculation down in smaller parts and focus on each of those individual parts. Once the individual parts work correctly, then link them together to form the whole.

49Membervalue = (Math.pow(-1, terms) * Math.pow(radAngle, (2*terms))) / factorial((2 * terms))); // inside a for loop in the main {}

terms changes because its inside a for loop, 1 - 11 terms, rad angle is the input by the user, and factorial calls the method.

The last part enters (2 * terms) into the factorial method to gimme a number. However the way this works out is Double * double / long. I get precision errors. Now if my answer is a long how can it be in decimal form? it recommends i cast it and write (long) infront of both doubles. The numbers i'm computing are going to have ALOT of decimal places. What do i do?

Thanks for all your help!!!

6,349Member:

: value = (Math.pow(-1, terms) * Math.pow(radAngle, (2*terms))) / factorial((2 * terms))); // inside a for loop in the main {}

:

: terms changes because its inside a for loop, 1 - 11 terms, rad angle is the input by the user, and factorial calls the method.

:

: The last part enters (2 * terms) into the factorial method to gimme a number. However the way this works out is Double * double / long. I get precision errors. Now if my answer is a long how can it be in decimal form? it recommends i cast it and write (long) infront of both doubles. The numbers i'm computing are going to have ALOT of decimal places. What do i do?

:

: Thanks for all your help!!!

:

:

I would cast the long into a double, because a long is an integer type, and you want to have the decimal places.

49Member49MemberI'm just confused now how I get all of the numbers to add up. Value = 1, then -0.5, then 0.04661. (theres alot more). But if its inside a for loop I'm not sure how to add them up, Term 1 = 1, term 2 = 1 + (-0.5), Term 3 (Term 2 + 0.04661); But i'm somewhat lost. I thought it was simple but everything i've tried fails.

6,349Member:

: I'm just confused now how I get all of the numbers to add up. Value = 1, then -0.5, then 0.04661. (theres alot more). But if its inside a for loop I'm not sure how to add them up, Term 1 = 1, term 2 = 1 + (-0.5), Term 3 (Term 2 + 0.04661); But i'm somewhat lost. I thought it was simple but everything i've tried fails.

:

I would use a function to calculate the terms based on some counter:

[code]

double taylor = 0;

for (int i = 0; i < Max; i++) {

taylor = taylor + term(i);

}

[/code]

49Member