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rphillips
Member Posts: **9**

Okay I have a problem I can't figure out. I have having to write a program that you input three numbers and the program tells you if it is Right triangle or not. I can't figure out the function that figures the three numbers. Can someone please help me.

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## Comments

75:

:

:

For a start, you'll actually need 6 numbers, an x and y co-ordinate for each point. If you assume a is where the right angle is, you can say if b has the same x value and c has the same y value, or if c has the same x value and a has the same y value, it is right angled. Do the same thing if b is the right angle and if c is:

ax = 10

ay = 20

bx = 5

by = 20

cx = 10

dy = 30

If ax = bx Then

If ay = cy Then

ans = True

End If

ElseIf ax = cx Then

If ay = by Then

ans = True

End If

ElseIf bx = ax Then

If by = cy Then

ans = True

End If

ElseIf bx = cx Then

If by = ay Then

ans = True

End If

ElseIf cx = ax Then

If cy = by Then

ans = True

End If

ElseIf cx = bx Then

If cy = ay Then

ans = True

End If

Else

ans = False

End If

ans is True if it is a right angled triangle.

Though this code only works if the right angle is laying parallel to the x or y axis!

To actually get it to work in general, simply compare the gradients of every pair of sides to the triangle. If the product of any pair = -1 then the lines of the gradients are set to bi-sect where the right angle is, this is a proof for determining a right angle triangle.

335: :

: :

: :

: For a start, you'll actually need 6 numbers, an x and y co-ordinate for each point. If you assume a is where the right angle is, you can say if b has the same x value and c has the same y value, or if c has the same x value and a has the same y value, it is right angled. Do the same thing if b is the right angle and if c is:

:

: ax = 10

: ay = 20

: bx = 5

: by = 20

: cx = 10

: dy = 30

:

: If ax = bx Then

: If ay = cy Then

: ans = True

: End If

: ElseIf ax = cx Then

: If ay = by Then

: ans = True

: End If

: ElseIf bx = ax Then

: If by = cy Then

: ans = True

: End If

: ElseIf bx = cx Then

: If by = ay Then

: ans = True

: End If

: ElseIf cx = ax Then

: If cy = by Then

: ans = True

: End If

: ElseIf cx = bx Then

: If cy = ay Then

: ans = True

: End If

: Else

: ans = False

: End If

:

: ans is True if it is a right angled triangle.

: Though this code only works if the right angle is laying parallel to the x or y axis!

:

: To actually get it to work in general, simply compare the gradients of every pair of sides to the triangle. If the product of any pair = -1 then the lines of the gradients are set to bi-sect where the right angle is, this is a proof for determining a right angle triangle.

:

??????

Ever heard of "Phytagoras"?

a + b = c sounds familiar?

If you just want to find out, if a triangle is right-angled, then you just have to check the above equation for all three possibilities (assuming a, b and c are the sides (Not the corners!) of your triangle. You have to calculate the length of each side through the x,y-Values of your corners, which is normal algebra).

if ((a + b = c) or (a + c = b) or (b + c = a))=False then

'I'm not a right-angled triangle

Else

'Yes, i'm a right-angled triangle

End if

------------------------------------------

Only stupidity of mankind and the universe

are infinite, but i'm not sure concerning

the universe. A. Einstein

748: : :

: : :

: : :

: : For a start, you'll actually need 6 numbers, an x and y co-ordinate for each point. If you assume a is where the right angle is, you can say if b has the same x value and c has the same y value, or if c has the same x value and a has the same y value, it is right angled. Do the same thing if b is the right angle and if c is:

: :

: : ax = 10

: : ay = 20

: : bx = 5

: : by = 20

: : cx = 10

: : dy = 30

: :

: : If ax = bx Then

: : If ay = cy Then

: : ans = True

: : End If

: : ElseIf ax = cx Then

: : If ay = by Then

: : ans = True

: : End If

: : ElseIf bx = ax Then

: : If by = cy Then

: : ans = True

: : End If

: : ElseIf bx = cx Then

: : If by = ay Then

: : ans = True

: : End If

: : ElseIf cx = ax Then

: : If cy = by Then

: : ans = True

: : End If

: : ElseIf cx = bx Then

: : If cy = ay Then

: : ans = True

: : End If

: : Else

: : ans = False

: : End If

: :

: : ans is True if it is a right angled triangle.

: : Though this code only works if the right angle is laying parallel to the x or y axis!

: :

: : To actually get it to work in general, simply compare the gradients of every pair of sides to the triangle. If the product of any pair = -1 then the lines of the gradients are set to bi-sect where the right angle is, this is a proof for determining a right angle triangle.

: :

:

: ??????

: Ever heard of "Phytagoras"?

:

: a + b = c sounds familiar?

:

: If you just want to find out, if a triangle is right-angled, then you just have to check the above equation for all three possibilities (assuming a, b and c are the sides (Not the corners!) of your triangle. You have to calculate the length of each side through the x,y-Values of your corners, which is normal algebra).

:

[code]

if ((a^2 + b^2 = c^2) or (a^2 + c^2 = b^2) or (b^2 + c^2 = a^2))=False then

'I'm not a right-angled triangle

Else

'Yes, i'm a right-angled triangle

End if

[/code]

Although

a^2 is less accurate in VB or VB.Net than a*a

Regards,

Dr M.

1[green] I can help you with your problem, lets break it into 3 steps.

1. Define the data types [/green]

[blue] Dim ShortSide, MediumSide, LongSide As String [/blue]

[green] 2. Ask the user for the variable values [/green]

[blue] ShortSide = InputBox("Enter The Short Side Length")

MediumSide = InputBox("Enter The Medium Side Length")

LongSide = InputBox("Enter The Long Side Length") [/blue]

[green] 3. Check whether the triangle is right angled and display result

[blue] If LongSide ^ 2 = ShortSide ^ 2 + MediumSide ^ 2 Then

MsgBox ("This triangle is right angled")

Else

MsgBox ("This triangle is not right angled")

End If [/blue]

Hope this helps you, any questions just ask me.