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Help with Bit Manipulation

WayneKeetWayneKeet Posts: 3Member
Hi all

I am new to VB programming and need some help.
I want to know if bit manipulation is possible in VB as in C++.

For example to see if a bit is a 1 or a 0 in a given word.
Also is there a function to convert a hex value to an int/float value.

Comments

  • BitByBit_ThorBitByBit_Thor Posts: 2,444Member
    : Hi all
    :
    : I am new to VB programming and need some help.
    : I want to know if bit manipulation is possible in VB as in C++.
    :
    : For example to see if a bit is a 1 or a 0 in a given word.
    : Also is there a function to convert a hex value to an int/float value.
    :
    :

    Integer = CInt("&H" & "67FF")
    Just prefix a hexidecimal sequence with &H and use a conversion function (like CInt).

    To check if a certain bit is set, you need to check by using powers of 2.

    For example, the first bit set is 2^0. The second bit set is 2^1.

    You can check any UNSIGNED number like this:
    If (Number And 2 ^ (BitNumber - 1)) Then
    MsgBox "Bit " & BitNumber & " is set (1)"
    End If

    You will, however, need to make an exception for the signed bits (since only the Byte is unsigned in VB).
    Basically, checking if a number is negative will return the sign bit.



    Greets...
    Richard

  • WayneKeetWayneKeet Posts: 3Member
    : : Hi all
    : :
    : : I am new to VB programming and need some help.
    : : I want to know if bit manipulation is possible in VB as in C++.
    : :
    : : For example to see if a bit is a 1 or a 0 in a given word.
    : : Also is there a function to convert a hex value to an int/float value.
    : :
    : :
    :
    : Integer = CInt("&H" & "67FF")
    : Just prefix a hexidecimal sequence with &H and use a conversion function (like CInt).
    :
    : To check if a certain bit is set, you need to check by using powers of 2.
    :
    : For example, the first bit set is 2^0. The second bit set is 2^1.
    :
    : You can check any UNSIGNED number like this:
    : If (Number And 2 ^ (BitNumber - 1)) Then
    : MsgBox "Bit " & BitNumber & " is set (1)"
    : End If
    :
    : You will, however, need to make an exception for the signed bits (since only the Byte is unsigned in VB).
    : Basically, checking if a number is negative will return the sign bit.
    :
    :
    :
    : Greets...
    : Richard
    :
    :
    Thanx Richard

    I entered your code and it worked fine.

    Again thank you.

    Regards
    Wayne


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