Operator Evaluation parentheses - Programmers Heaven

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# Operator Evaluation parentheses

Posts: 3Member
I am a little confused about using the correct amount of parentheses around operators.

For example, which one of these would be correct:

1. if (length(s) >= 2) and (s[1] = 'A') or (s[1] = 'B') then ...
2. if (length(s) >= 2) and ((s[1] = 'A') or (s[1] = 'B')) then ...

I am assuming 2. is the correct method, but I want to be sure. They seem to both function correctly, though...

• Posts: 6,349Member
: I am a little confused about using the correct amount of parentheses around operators.
:
: For example, which one of these would be correct:
:
: 1. if (length(s) >= 2) and (s[1] = 'A') or (s[1] = 'B') then ...
: 2. if (length(s) >= 2) and ((s[1] = 'A') or (s[1] = 'B')) then ...
:
:
: I am assuming 2. is the correct method, but I want to be sure. They seem to both function correctly, though...
:
They both work, although differently. The first is actually this:
[code]
if ((length(s) >= 2) and (s[1] = 'A')) or (s[1] = 'B') then ...
[/code]
This is because the AND and OR are on the same priority level, mathematically speaking. Thus they are evaluated from left to right.
As to the question, which is correct, that depends on what you want to evaluate. If you want your strings to have a length of 2+ and (start with either A or the second is correct. The first is correct if string may be (length of 2+ and start with A) or (any length and start with .