It looks like you're new here. If you want to get involved, click one of these buttons!

- 140.8K All Categories
- 104.4K Programming Languages
- 6.4K Assembler Developer
- 1.8K Basic
- 39.8K C and C++
- 4.2K C#
- 7.9K Delphi and Kylix
- 4 Haskell
- 9.6K Java
- 4.1K Pascal
- 1.3K Perl
- 1.9K PHP
- 507 Python
- 48 Ruby
- 4.3K VB.NET
- 1.6K VBA
- 20.8K Visual Basic
- 2.6K Game programming
- 310 Console programming
- 88 DirectX Game dev
- 1 Minecraft
- 110 Newbie Game Programmers
- 2 Oculus Rift
- 8.9K Applications
- 1.8K Computer Graphics
- 726 Computer Hardware
- 3.4K Database & SQL
- 521 Electronics development
- 1.6K Matlab
- 627 Sound & Music
- 256 XML Development
- 3.3K Classifieds
- 193 Co-operative Projects
- 180 For sale
- 189 FreeLance Software City
- 1.9K Jobs Available
- 600 Jobs Wanted
- 201 Wanted
- 2.9K Microsoft .NET
- 1.7K ASP.NET
- 1.1K .NET General
- 3K Miscellaneous
- 3 Join the Team
- 0 User Profiles
- 349 Comments on this site
- 59 Computer Emulators
- 1.9K General programming
- 178 New programming languages
- 595 Off topic board
- 159 Mobile & Wireless
- 33 Android
- 124 Palm Pilot
- 335 Multimedia
- 151 Demo programming
- 184 MP3 programming
- 0 Bash scripts
- 18 Cloud Computing
- 52 FreeBSD
- 1.7K LINUX programming
- 367 MS-DOS
- 0 Shell scripting
- 320 Windows CE & Pocket PC
- 4.1K Windows programming
- 882 Software Development
- 405 Algorithms
- 68 Object Orientation
- 86 Project Management
- 88 Quality & Testing
- 234 Security
- 7.5K WEB-Development
- 1.8K Active Server Pages
- 61 AJAX
- 2 Bootstrap Themes
- 55 CGI Development
- 19 ColdFusion
- 222 Flash development
- 1.4K HTML & WEB-Design
- 1.4K Internet Development
- 2.2K JavaScript
- 33 JQuery
- 285 WEB Servers
- 119 WEB-Services / SOAP

turbo pascal
Posts: **13**Member

in Matlab

Hi, I have a program that should read a line of text and output the number of words in the line and the number of occurrences of each letter. the output of the letters must be in alphabetical order counting both upper and lowercase versions .(ex input: Hello Hi. And the output: there are 2 words

1 e

2 h

1 i

2 l

1 o

I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

do

{

finish = 0;

for ( i = 0; i < x - 1; i++) // sorting the string..

{

if (s[i] > s[i + 1])

{

hold = s[i];

s[i] = s[i + 1];

s[i + 1] = hold;

finish = 1;

}

}

}while (finish != 0) ;

* so I decided to delete everything that is not a letter but it didn't work…

for (i=0; i<size; i++) // string contains only letters..

if (isalpha(s[i]))

temp[i]=s[i] ;

* and I thought of another way that it didn't work..

for (i=0; i<size; i++) // string contains only letters..

if (!isalpha(s[i]))

s[i]=s[i+1] ;

* finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

for ( i=0;i<x;i++) //counting the occurrences of each letter..

{ for(j=0;j<x;j++)

{

if (s[i]==s[j])

a++ ;

}

cout << s[i] << " occured : " <<a << endl;

a=0;

}

cout << endl;

return 0;

}

1 e

2 h

1 i

2 l

1 o

I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

do

{

finish = 0;

for ( i = 0; i < x - 1; i++) // sorting the string..

{

if (s[i] > s[i + 1])

{

hold = s[i];

s[i] = s[i + 1];

s[i + 1] = hold;

finish = 1;

}

}

}while (finish != 0) ;

* so I decided to delete everything that is not a letter but it didn't work…

for (i=0; i<size; i++) // string contains only letters..

if (isalpha(s[i]))

temp[i]=s[i] ;

* and I thought of another way that it didn't work..

for (i=0; i<size; i++) // string contains only letters..

if (!isalpha(s[i]))

s[i]=s[i+1] ;

* finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

for ( i=0;i<x;i++) //counting the occurrences of each letter..

{ for(j=0;j<x;j++)

{

if (s[i]==s[j])

a++ ;

}

cout << s[i] << " occured : " <<a << endl;

a=0;

}

cout << endl;

return 0;

}

About & Contact / Terms of use / Privacy statement / Publisher: Lars Hagelin

Programmers Heaven articles / Programmers Heaven files / Programmers Heaven uploaded content / Programmers Heaven C Sharp ebook / Operated by CommunityHeaven LLC

© 1997-2013 Programmersheaven.com - All rights reserved.

## Comments

8Member: Hi, I have a program that should read a line of text and output the number of words in the line and the number of occurrences of each letter. the output of the letters must be in alphabetical order counting both upper and lowercase versions .(ex input: Hello Hi. And the output: there are 2 words

: 1 e

: 2 h

: 1 i

: 2 l

: 1 o

:

: I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

: do

: {

: finish = 0;

: for ( i = 0; i < x - 1; i++) // sorting the string..

: {

: if (s[i] > s[i + 1])

: {

: hold = s[i];

: s[i] = s[i + 1];

: s[i + 1] = hold;

:

: finish = 1;

: }

: }

: }while (finish != 0) ;

:

: * so I decided to delete everything that is not a letter but it didn't work…

:

: for (i=0; i<size; i++) // string contains only letters..

: if (isalpha(s[i]))

: temp[i]=s[i] ;

: * and I thought of another way that it didn't work..

:

: for (i=0; i<size; i++) // string contains only letters..

: if (!isalpha(s[i]))

: s[i]=s[i+1] ;

:

: * finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

:

: for ( i=0;i<x;i++) //counting the occurrences of each letter..

: { for(j=0;j<x;j++)

: {

: if (s[i]==s[j])

: a++ ;

: }

: cout << s[i] << " occured : " <<a << endl;

: a=0;

: }

: cout << endl;

: return 0;

: }

:

:

:

:

:

:

: